Cubic Equation
with
Integer Co-efficient
( only for real+complex roots; for real roots this will fail. click here)
*The cubic equation with real co-efficient will have 3 roots.
These roots are either all real or 1 real, 2 complex with one being
the complex conjugate of another. * Let the equation be ax3 + bx2 + cx + d =0 * to find the roots , let us calculate the following:- Δ0= b2 - 3ac ; when a=1, Δ0= b2 - 3c Δ'0= - Δ0/9 =c/3 - b2/9 (when a=1) Δ1= 2b3 - 9abc + 27a2d ; when a=1, Δ1= 2b3 - 9bc + 27d Δ'1= - Δ1/54=(b/3)*(c/2) -(b/3)3 - d/2 (when a=1) D=Δ'30+Δ'21 ; if D < 0, all roots are real, distinct if D = 0, all roots real, at least two are same. if D > 0, one root real, rest two are complex conjugates of each other. del3a=√(Δ21 -4Δ30) C = ∛[(Δ1 + √(Δ21 -4Δ30))/2] x1=(1/-3a)(b+ C + Δ0 /C) x(2&3) =b + ξ2C + Δ0 /ξ2C where ξ=(-1+√3i) /2 and ξ2 =-(1+√3i) / 2; x2=(b - C/2 - Δ0/2C ) + (C2 -Δ0 )i /(2√3aC) ; x3=(b - C/2 - Δ0/2C ) - (C2 -Δ0 )i /(2√3aC) ; * If discriminant of the cubic > 0 , then there are 3 distinct real roots. If discriminant of the cubic < 0 , then there is 1 real and 2 complex roots , one being the complex conjugate of the other. If discriminant of the cubic = 0 , then all real & multiple roots. * In depressed cubic equation, ti = xi + b/3a where i=1,2,3 |